What is the span, in inches of water, of a differential pressure transmitter used to measure the full level of a tank that is 5-ft, 6-in. high and has a specific gravity of 0.9?

To determine the span of a differential pressure transmitter used to measure the full level of a tank, it is essential to understand both the height of the tank and the specific gravity of the fluid being measured.

First, convert the height of the tank from feet and inches to inches only. Since there are 12 inches in a foot, a height of 5 feet and 6 inches equates to:

5 ft * 12 in/ft = 60 in

Adding the additional 6 inches gives us:

60 in + 6 in = 66 in

Next, the span of the transmitter is determined by calculating the pressure that corresponds to the height of the fluid in the tank. The formula for pressure in inches of water is given by:

Pressure (in inches of water) = Height (in inches) * Specific Gravity

Using the known height of 66 inches and the specific gravity of 0.9:

Pressure = 66 in * 0.9 = 59.4 in of water

Thus, the span of the differential pressure transmitter is 59.4 inches of water. This is the correct response as it accurately reflects the measurement based on the fluid's specific gravity and the tank's height.